Question
If A + B = 90° and $\tan\text{A}=\frac{3}{4},$ what is cot B?
✓
Answer
We have,
$\text{A}+\text{B}=90^\circ$
So, $\text{A}=90^\circ-\text{B}$
And, $\tan\text{A}=\frac{3}{4}$
$\Rightarrow\tan\text{A}=\tan(90^\circ-\text{B})$
$\Rightarrow\cot\text{B}=\frac{3}{4}$
$\text{A}+\text{B}=90^\circ$
So, $\text{A}=90^\circ-\text{B}$
And, $\tan\text{A}=\frac{3}{4}$
$\Rightarrow\tan\text{A}=\tan(90^\circ-\text{B})$
$\Rightarrow\cot\text{B}=\frac{3}{4}$
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