If a + b + c = 0, then a × b = - Vidyadip

MCQ

If a + b + c = 0, then a × b =

A
c × a
B
b × c
C
0
✓
Both (a) and (b)

✓

Answer

Correct option: D.

Both (a) and (b)

Both (a) and (b)

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from VECTOR ALGEBRA→VECTOR ALGEBRA — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The area bounded by the curve $y^2=x$, line $y=4$ and $y-$axis is

The shortest distance of the point $(a, b, c)$ from the $x$ - axis is

$\int_{}^{} {\frac{{5({x^6} + 1)}}{{{x^2} + 1}}dx = } $

Choose the most correct of the following statements relating to primal$-$dual linear programming problems:

$\sin [{\cot ^{ - 1}}(\cos {\tan ^{ - 1}}x)] =$

Let $\mathrm{ABC}$ be a triangle of area $15 \sqrt{2}$ and the vectors $\overrightarrow{\mathrm{AB}}=\hat{i}+2 \hat{j}-7 \hat{k}, \quad \overrightarrow{B C}=a \hat{i}+b \hat{j}+c \hat{k}$ and $\overrightarrow{\mathrm{AC}}=6 \hat{\mathrm{i}}+\mathrm{d} \hat{\mathrm{j}}-2 \hat{\mathrm{k}}, \mathrm{d}>0$. Then the square of the length of the largest side of the triangle $\mathrm{ABC}$ is....................

Let the population ofrabbits surviving at time $t$ be governed by the differential equation $\frac{{dp\left( t \right)}}{{dt}} = \frac{1}{2}p\left( t \right) - 200$ . If $ p(0)=100 $ ,then $p(t)$ equals :

If direction ratios of two lines are $5,\,\, - 12,\,13$ and $ - 3,\,4,\,5$ then the angle between them is

If the function $f$ defined on $\left( {\frac{\pi }{6},\frac{\pi }{3}} \right)$ by $f\,(x)\, = \,\left\{ {\begin{array}{*{20}{c}}
{\frac{{\sqrt 2 \,\cos \,x - \,1}}{{\cot \,x\, - \,1}}\,,\,x\, \ne \,\frac{\pi }{4}}\\
{k,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\, = \frac{\pi }{4}}
\end{array}} \right.$ is continuous, then $k$ is equal to

$\text{The value of}\ \hat{\text{i}}\cdot(\hat{\text{j}}\times\hat{\text{k}})+\hat{\text{j}}\cdot(\hat{\text{i}}\times\hat{\text{k}})+\hat{\text{k}}\cdot(\hat{\text{i}}\times\hat{\text{j}})\ \text{is}$