Download App

Polynomials — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsPolynomials1 Mark
MCQ
If $a + b + c = 0,$ then $\Big(\frac{\text{a}^2}{\text{bc}}+\frac{\text{b}^2}{\text{ca}}+\frac{\text{c}^2}{\text{ab}}\Big)=$
  • A
    $1$
  • ✓
    $3$
  • C
    $0$
  • D
    $2$
✓

Answer

Correct option: B.
$3$
 $\Big(\frac{\text{a}^2}{\text{bc}}+\frac{\text{b}^2}{\text{ca}}+\frac{\text{c}^2}{\text{ab}}\Big)$
$=\frac{\text{a}^3+\text{b}^3+\text{c}^3}{\text{abc}}$
Since $a+b+c=0$, then $a^3+b^3+c^3=3 a b c$Therefore,
$=\frac{3\text{abc}}{\text{abc}}$
$=3$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q" from Polynomials→Polynomials — all question types→Maths STD 9 question papers→Gujarat Board STD 9 question papers→Gujarat Board question paper generator→

Similar questions

If $x-2$ is a factor of $x^2+3 a x-2 a$, then $a=$
→
The constant distance of a point on a circle from the centre of the circle is called.
→
The number of planes passing through 3 non-collinear points is:
→
$\sqrt{11 \sqrt{11 \sqrt{11 \ldots .} 4 \text { terms }}}$ is equal to
→
If $\frac{a}{b}+\frac{b}{a}=-1$ then $\left(a^3-b^3\right)=$ ?
​​​​
→
The class mark of the class $90-120$ is:
→
If the length of a chord of a circle is $16\ cm$ and is at a distance of $15\ cm$ from the centre of the circle, then the radius of the circle is:
→
Find out the mode of the following: $5, 4, 3, 5, 6, 6, 6, 5, 4, 5, 5, 3, 2, 1.$
→
The line drawn from the center of the circle to any point on its circumference is called:
→
Angles of a triangle are in the ratio $2 : 4 : 3$. The smallest angle of the triangle is:
→