If a, b, c are all nonzero and a + b + c = 0, prove that: a^2 bc + b^2 ca + c^2 ab =3

a+b+c=0 a^3+b^3+c^3=3 a b c Thus, We have: ( a^2 bc + b^2 ca + c^2 ab )= a^3+b^3+c^3 abc = 3abc abc =3

If a, b, c are all nonzero and a + b + c = 0, prove that: a^2 bc …

Find the remainder when $x^3-a x^2+6 x-a$ is divided by $x - a$.

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