MCQ
If $a, b, c$  are mutually perpendicular unit vectors, then $|a + b + c|\,\, = $
  • $\sqrt 3 $
  • B
    $3$
  • C
    $1$
  • D
    $0$

Answer

Correct option: A.
$\sqrt 3 $
a
(a) Three mutually perpendicular unit vectors $ = a$, $b$ and $c$.

Therefore $|a|\, = \,|b|\, = \,|c|\, = 1$ and $a.b = b.c = c.a = 0$.

We know that

$|a + b + c{|^2} = (a + b + c)\,.\,(a + b + c) = \,\,|a{|^2} + |b{|^2}$

$ + |c{|^2} + 2(a\,.\,b\,\, + b\,.\,c\, + c\,.\,a) = 1 + 1 + 1 + 0 = 3$

or $|a + b + c|\, = \sqrt 3 .$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free