Question
If A, B, C are the interior angles of a $\triangle\text{ABC},$ show that:
$\cos\frac{\text{B+C}}{2}=\sin\frac{\text{A}}{2}$

Answer

$\cos\frac{\text{B+C}}{2}=\sin\frac{\text{A}}{2}$
$=\text{L.H.S}$
$=\cos\frac{\text{B+C}}{2}$
$=\cos\frac{180^\circ-\text{A}}{2}$
$=\cos\Big(90^\circ-\frac{\text{A}}{2}\Big)$
$=\sin\frac{\text{A}}{2}$
$=\text{R.H.S}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free