Download App

Sequences and Series — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSequences and Series1 Mark
MCQ
If $a, b, c, d$ are any four consecutive coefficients of any expanded binomial, then $\frac{\text{a}+\text{b}}{a},\frac{\text{b}+\text{c}}{b},\frac{\text{c }+\text{d}}{c}$ are in:
  • A
    $AP$
  • B
    $GP$
  • ✓
    $HP$
  • D
    None of these
✓

Answer

Correct option: C.
$HP$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Sequences and Series→Sequences and Series — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

The vertices of a triangle $OBC$ are $(0,\;0),\;( - 3,\; - 1)$ and $( - 1,\; - 3)\;$ respectively. Then the equation of line parallel to $BC$ which is at $\frac{1}{2}$unit distant from origin and cuts $OB$ and $OC$, is
→
The number of $3 \times 3$ matrices $A$ whose entries are either $0$ or $1$ and for which the system $\mathrm{A}\left[\begin{array}{l}\mathrm{x} \\ \mathrm{y} \\ \mathrm{z}\end{array}\right]=\left[\begin{array}{l}1 \\ 0 \\ 0\end{array}\right]$ has exactly two distinct solutions, is
→
${\tan ^2}\theta + {\cot ^2}\theta $ is
→
Let ${S_1},{S_2},......,{S_{101}}$ be the consecutive terms of an $A.P$ . If $\frac{1}{{{S_1}{S_2}}} + \frac{1}{{{S_2}{S_3}}} + .... + \frac{1}{{{S_{100}}{S_{101}}}} = \frac{1}{6}$ and ${S_1} + {S_{101}} = 50$ , then $\left| {{S_1} - {S_{101}}} \right|$ is equal to
→
Let $A$ be a $3 \times 3$ matrix having entries from. the set $\{-1,0,1\}$. The number of all such matrices A having sum of all the entries equal to $5$ , is
→
If ${(1 + x - 2{x^2})^6} = 1 + {a_1}x + {a_2}{x^2} + .... + {a_{12}}{x^{12}}$, then the expression ${a_2} + {a_4} + {a_6} + .... + {a_{12}}$ has the value
→
If $z = i\,\log \,(2 - \sqrt 3 ),$ then $\cos z = $
→
Consider the statement: $“P(n) : n^2 – n + 41$ is prime.” Then which one of the following is true?
→
Given the sets $A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}$, then $A \cup(B \cap C)$ is
→
The events $A, B, C$ are mutually exclusive events such that $\text{P(A)}=\frac{(3\text{x}+1)}{3,\text{P(B)}}=\frac{(\text{x}-1)}{4\text{ and}\text{ P}}\text{(C)}=\frac{(1-2\text{x})}{4}.$The set of possible values of $x$ are in the interval:
→