MCQ
If $a b c=6$ and $a+b+c=6$, then $\frac{1}{a c}+\frac{1}{a b}+\frac{1}{b c}=$
- A2
- ✓1
- C3
- D$0$
✓
Answer
Correct option: B.
1
(b)
We have, $a+b+c=6$ and $a b c=6$
$\Rightarrow \quad \frac{a+b+c}{a b c}=\frac{6}{6} \Rightarrow \frac{1}{b c}+\frac{1}{c a}+\frac{1}{a b}=1$
We have, $a+b+c=6$ and $a b c=6$
$\Rightarrow \quad \frac{a+b+c}{a b c}=\frac{6}{6} \Rightarrow \frac{1}{b c}+\frac{1}{c a}+\frac{1}{a b}=1$
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