MCQ
If (a, b) lies on circle with centre as origin, then its radius will be:
- A$\text{a} - \text{ b}$
- B$\text{a + b}$
- C$\sqrt{\text{a}^2+\text{b}^2}$
- D$\text{a}^2+\text{b}^2$
If (a, b) lies on circle with centre as origin, then its radius will be:
Solution:
We know the formula,
The equation of a circle of radius r and centre the origin is
x2 + y2 = r2
Here the center is (a, b)
so Radius, $\text{r} = \sqrt{\text{a}^{2} + \text{b}^{2}}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
The domain of the function f given by $\text{f(x)}=\frac{\text{x}^2+2\text{x}+1}{\text{x}^2-\text{x}-6}.$
The contrapositive of the statement.
“If p, then q”, is.