Question
If a function f : R → R be defined by: $\text{f(x)}=\begin{cases}3\text{x}-2,&\text{ x}<0\\1,&\text{x}=0\\4\text{x}+1,&\text{ x}>0\end{cases}$ Find: f(1), f(-1), f(0) and f(2)
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Answer
We have, $\text{f(x)}=\begin{cases}3\text{x}-2,&\text{ x}<0\\1,&\text{x}=0\\4\text{x}+1,&\text{ x}>0\end{cases}$ Now, f(1) = 4 × 1 + 1 = 5 f(-1) = 3 × (-1) - 2 = -3 - 2 = -5 f(0) = 1 and, f(2) = 4 × 2 + 1 = 9 $\therefore$ f(1) = 5, f(-1) = -5 f(0) = 1, f(2) = 9
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