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Functions — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsFunctions3 Marks
Question
If a function f : R → R be defined by:
$\text{f(x)}=\begin{cases}3\text{x}-2,&\text{ x}<0\\1,&\text{x}=0\\4\text{x}+1,&\text{ x}>0\end{cases}$
Find: f(1), f(-1), f(0) and f(2)
✓

Answer

We have,
$\text{f(x)}=\begin{cases}3\text{x}-2,&\text{ x}<0\\1,&\text{x}=0\\4\text{x}+1,&\text{ x}>0\end{cases}$
Now, f(1) = 4 × 1 + 1 = 5
f(-1) = 3 × (-1) - 2
= -3 - 2 = -5
f(0) = 1
and, f(2) = 4 × 2 + 1 = 9
$\therefore$ f(1) = 5, f(-1) = -5
f(0) = 1, f(2) = 9

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