MCQ
If $A$ is a singular matrix, then $\text{adj A}$ is.
  • A
    non$−$singular
  • singular
  • C
    symmetric
  • D
    not defined

Answer

Correct option: B.
singular
Given $∣A∣ = 0$
We know $∣\text{adj A}∣ = ∣A∣ n - 1$
$\therefore\ ∣\text{adj A}∣ = 0$
Hence$, \text{adj A}$ is singular

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