2&3\\
5&{ - 1}
\end{array}} \right]$ , then $AB$ is equal to
- A$\left[ {\begin{array}{*{20}{c}}
4&{ - 2}\\
1&{ - 4}
\end{array}} \right]$ - ✓$\left[ {\begin{array}{*{20}{c}}
4&{ - 2}\\
{ - 1}&{ - 4}
\end{array}} \right]$ - C$\left[ {\begin{array}{*{20}{c}}
{ - 4}&2\\
1&4
\end{array}} \right]$ - D$\left[ {\begin{array}{*{20}{c}}
{ - 4}&{ - 2}\\
{ - 1}&4
\end{array}} \right]$