Question
If A is square matrix such that A2 = A, then show that (I + A)3 = 7A + I.

Answer

We know that, A.I = I.A

So, A and I are commutative.

Therefore we can expand (I + A)3 like real number expansion.

So, (I + A)3 = I3 + 3I2A + 3IA2 + A3

= I + 3IA + 3A2 + AA2 $($as In = I, $\text{n}\in\text{N})$

= I + 3A + 3A + AA

= I + 3A + 3A + A2

= I + 3A + 3A + A = I + 7A

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