Question
If A is square matrix such that A2 = A, then show that (I + A)3 = 7A + I.
= I + 3IA + 3A2 + AA2
$($as In = I, $\text{n}\in\text{N})$= I + 3A + 3A + AA
= I + 3A + 3A + A2
= I + 3A + 3A + A = I + 7A
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| X = xi: | 1 | 2 | 3 | 4 |
| P(X = xi): | 2k | 4k | 3k | k |