If a kite in the shape of an isosceles triangle of base 8 cm and each equal side 6 cm is to be made, the area of paper required to make the kite, is
A$10 \sqrt{2} cm^2$
B$8 \sqrt{5} cm^2$
C$10 \sqrt{2} cm^2$
D$8 cm^2$
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B$8 \sqrt{5} cm^2$
(b) $8 \sqrt{2} cm^2$ Here, $a=8 cm$ and $b=6 cm$. $\therefore \quad \text { Area of kite }=\frac{a}{4} \sqrt{4 b^2-a^2}=\frac{8}{4} \sqrt{4 \times 36-64}=2 \sqrt{80} cm^2=8\sqrt{5} cm^2$
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