MCQ
If $A = \left[ {\begin{array}{*{20}{c}}0&1\\0&0\end{array}} \right]$and $AB = O$, then $B =$
  • A
    $\left[ {\begin{array}{*{20}{c}}1&1\\1&1\end{array}} \right]$
  • B
    $\left[ {\begin{array}{*{20}{c}}0&1\\{ - 1}&0\end{array}} \right]$
  • C
    $\left[ {\begin{array}{*{20}{c}}0&{ - 1}\\1&0\end{array}} \right]$
  • $\left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right]$

Answer

Correct option: D.
$\left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right]$
d
(d) Since $\left[ {\begin{array}{*{20}{c}}0&1\\0&0\end{array}} \right]\,\left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}0&0\\0&0\end{array}} \right] = O = AB$
==> $B = \left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right]$.

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