MCQ
If $A = \left[ {\begin{array}{*{20}{c}}{1/3}&2\\0&{2x - 3}\end{array}} \right],B = \left[ {\begin{array}{*{20}{c}}3&6\\0&{ - 1}\end{array}} \right]$and $AB = I$, then $x =$
- A$-1$
- ✓$1$
- C$0$
- D$2$
(As given)
$\Leftrightarrow \,\,3 - 2x = 1$ or $x = 1$.
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that $S$ lies on the diagonal OT. If $\overrightarrow{ p }=\overrightarrow{ SP }, \overrightarrow{ q }=\overrightarrow{ SQ }, \overrightarrow{ r }=\overrightarrow{ SR }$ and $\overrightarrow{ t }=\overrightarrow{ ST }$, then the value of $|(\overrightarrow{ p } \times \overrightarrow{ q }) \times(\overrightarrow{ r } \times \overrightarrow{ t })|$ is. . . . . . ..