MCQ
If $A = \left( {\begin{array}{*{20}{c}}1&{ - 2}&1\\2&1&3\end{array}} \right)$ and $B = \left( {\begin{array}{*{20}{c}}2&1\\3&2\\1&1\end{array}} \right)$, then ${(AB)^T}$ is equal to
- A$\left( {\begin{array}{*{20}{c}}{ - 3}&{ - 2}\\{10}&7\end{array}} \right)$
- ✓$\left( {\begin{array}{*{20}{c}}{ - 3}&{10}\\{ - 2}&7\end{array}} \right)$
- C$\left( {\begin{array}{*{20}{c}}{ - 3}&7\\{10}&2\end{array}} \right)$
- DNone of these