MCQ
If $A = \left[ {\begin{array}{*{20}{c}}1&3&0\\{ - 1}&2&1\\0&0&2\end{array}} \right],B = \left[ {\begin{array}{*{20}{c}}2&3&4\\1&2&3\\{ - 1}&1&2\end{array}} \right]$, then $AB =$
  • A
    $\left[ {\begin{array}{*{20}{c}}5&9&{13}\\{ - 1}&2&4\\{ - 1}&2&4\end{array}} \right]$
  • $\left[ {\begin{array}{*{20}{c}}5&9&{13}\\{ - 1}&2&4\\{ - 2}&2&4\end{array}} \right]$
  • C
    $\left[ {\begin{array}{*{20}{c}}1&2&4\\{ - 1}&2&4\\{ - 2}&2&4\end{array}} \right]$
  • D
    None of these

Answer

Correct option: B.
$\left[ {\begin{array}{*{20}{c}}5&9&{13}\\{ - 1}&2&4\\{ - 2}&2&4\end{array}} \right]$
b
(b) $AB = \left[ {\begin{array}{*{20}{c}}{\,\,5}&9&{13}\\{ - 1}&2&4\\{\,\, - 2}&2&4\end{array}} \right]$.

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