If A = [ * 20 c 3&1 - 1 &2 ], then A^2 = - Vidyadip

MCQ

If $A = \left[ {\begin{array}{*{20}{c}}3&1\\{ - 1}&2\end{array}} \right]$, then ${A^2} = $

A
$\left[ {\begin{array}{*{20}{c}}8&{ - 5}\\{ - 5}&3\end{array}} \right]$
B
$\left[ {\begin{array}{*{20}{c}}8&{ - 5}\\5&3\end{array}} \right]$
C
$\left[ {\begin{array}{*{20}{c}}8&{ - 5}\\{ - 5}&{ - 3}\end{array}} \right]$
✓
$\left[ {\begin{array}{*{20}{c}}8&5\\{ - 5}&3\end{array}} \right]$

✓

Answer

Correct option: D.

$\left[ {\begin{array}{*{20}{c}}8&5\\{ - 5}&3\end{array}} \right]$

d
(d) $A = \left[ {\begin{array}{*{20}{c}}3&1\\{ - 1}&2\end{array}} \right]$

${A^2} = A.A = \left[ {\begin{array}{*{20}{c}}3&1\\{ - 1}&2\end{array}} \right]\,\left[ {\begin{array}{*{20}{c}}3&1\\{ - 1}&2\end{array}} \right]$

${A^2} = \left[ {\begin{array}{*{20}{c}}8&5\\{ - 5}&3\end{array}} \right]$.

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