MCQ
If $A = \left[ {\begin{array}{*{20}{c}}4&{x + 2}\\{2x - 3}&{x + 1}\end{array}} \right]$is symmetric, then $ x =$
  • A
    $3$
  • $5$
  • C
    $2$
  • D
    $4$

Answer

Correct option: B.
$5$
b
(b) Since the given matrix is symmetric, therefore

${a_{12}} = {a_{21}} \Rightarrow x + 2 = 2x - 3 \Rightarrow x = 5$.

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