MCQ
If $A = \left[ {\begin{array}{*{20}{c}}5&2\\3&1\end{array}} \right],$then ${A^{ - 1}}$=
  • A
    $\left[ {\begin{array}{*{20}{c}}1&{ - 2}\\{ - 3}&5\end{array}} \right]$
  • $\left[ {\begin{array}{*{20}{c}}{ - 1}&2\\3&{ - 5}\end{array}} \right]$
  • C
    $\left[ {\begin{array}{*{20}{c}}{ - 1}&{ - 2}\\{ - 3}&{ - 5}\end{array}} \right]$
  • D
    $\left[ {\begin{array}{*{20}{c}}1&2\\3&5\end{array}} \right]$

Answer

Correct option: B.
$\left[ {\begin{array}{*{20}{c}}{ - 1}&2\\3&{ - 5}\end{array}} \right]$
b
(b) Since $\left[ {\begin{array}{*{20}{c}}5&2\\3&1\end{array}} \right]\,\left[ {\begin{array}{*{20}{c}}{ - 1}&2\\3&{ - 5}\end{array}} \right]\, = \left[ {\begin{array}{*{20}{c}}1&0\\0&1\end{array}} \right]$.

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