MCQ
If $A = \left[ {\begin{array}{*{20}{c}}\alpha &0\\1&1\end{array}} \right]$ and $B = \left[ {\begin{array}{*{20}{c}}1&0\\5&1\end{array}} \right]$, then value of $\alpha $for which ${A^2} = B$, is
- A$1$
- B$-1$
- C$4$
- ✓No real values
Clearly, no real value of $\alpha$.
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If $\text{A}=\begin{bmatrix}1&0\\0&1\end{bmatrix},$ then A2 is equal to:
$\begin{bmatrix}0&1\\1&0\end{bmatrix}$
$\begin{bmatrix}1&0\\1&0\end{bmatrix}$
$\begin{bmatrix}0&1\\0&1\end{bmatrix}$
$\begin{bmatrix}1&0\\0&1\end{bmatrix}$