MCQ
If $A = \left[ {\begin{array}{*{20}{c}}\alpha &2\\2&\alpha \end{array}} \right]$ and $|{A^3}|$=125, then $\alpha = $
- ✓$ \pm $ $3$
- B$ \pm $ $2$
- C$ \pm $ $5$
- D$0$
$ \Rightarrow $ $|A| = 5$ $ \Rightarrow $ ${\alpha ^2} - 4 = 5 \Rightarrow \alpha = \pm 3$.
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