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Matrices — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsMatrices1 Mark
Question
If A = $\left[\begin{array}{cc} {\cos \alpha} & {-\sin \alpha} \\ {\sin \alpha} & {\cos \alpha} \end{array}\right]$, and A + A' = I, if the value of $\alpha$ is
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Answer

Given $A=\left[\begin{array}{cc} {\cos \alpha} & {-\sin \alpha} \\ {\sin \alpha} & {\cos \alpha} \end{array}\right]$ 
Therefore, $A^{\prime}=\left[\begin{array}{cc} {\cos \alpha} & {\sin \alpha} \\ {-\sin \alpha} & {\cos \alpha} \end{array}\right]$ 
Also given that A + A' = I    ...(1)
(Putting the values in equation (1))
$\left[\begin{array}{cc} {\cos \alpha} & {-\sin \alpha} \\ {\sin \alpha} & {\cos \alpha} \end{array}\right]+\left[\begin{array}{cc} {\cos \alpha} & {\sin \alpha} \\ {-\sin \alpha} & {\cos \alpha} \end{array}\right]=\left[\begin{array}{ll} {1} & {0} \\ {0} & {1} \end{array}\right]$ 
$\Rightarrow$ $\left[\begin{array}{cc} {\cos \alpha+\cos \alpha} & {-\sin \alpha+\sin \alpha} \\ {\sin \alpha-\sin \alpha} & {\cos \alpha+\cos \alpha} \end{array}\right]=\left[\begin{array}{ll} {1} & {0} \\ {0} & {1} \end{array}\right]$ 
$\Rightarrow$ $\left[\begin{array}{cc} {2 \cos \alpha} & {0} \\ {0} & {2 \cos \alpha} \end{array}\right]=\left[\begin{array}{ll} {1} & {0} \\ {0} & {1} \end{array}\right]$ 
We know the two matrices are equal only when all their corresponding elements or entries are equal i.e. if A = B, then aij and bij for all i and j.
This implies,
$2 \cos \alpha=1$ 
$\Rightarrow$ $\cos \alpha=\frac{1}{2}$ 
$\Rightarrow$ $\cos \alpha=\cos \frac{\pi}{3}~~~ ...\left(\because \cos \frac{\pi}{3}=\frac{1}{2}\right)$ 
$\Rightarrow$ $\alpha=\frac{\pi}{3}$

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