MCQ
If $A =\left[\begin{array}{cc} i & 0 \\ 0 & \frac{ i }{2}\end{array}\right]$ where $( i =\sqrt{-1})$, then $A ^{-1}=$
  • A
    $\left[\begin{array}{ll} i & 0 \\ 0 & \frac{ i }{2}\end{array}\right]$
  • $\left[\begin{array}{cc}- i & 0 \\ 0 & -2 i \end{array}\right]$
  • C
    $\left[\begin{array}{cc} i & 0 \\ 0 & 2 i \end{array}\right]$
  • D
    $\left[\begin{array}{cc}0 & i \\ 2 i & 0\end{array}\right]$

Answer

Correct option: B.
$\left[\begin{array}{cc}- i & 0 \\ 0 & -2 i \end{array}\right]$
(B) $|A|=-\frac{1}{2} \neq 0$
$\therefore \quad A ^{-1}=\frac{1}{\frac{-1}{2}}\left[\begin{array}{ll}\frac{ i }{2} & 0 \\ 0 & i \end{array}\right]=\left[\begin{array}{cc}- i & 0 \\ 0 & -2 i \end{array}\right]$ ...[Using Shortcut 2]

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