Question
If $A =\left[\begin{array}{ll}0 & 1 \\ 1 & 2\end{array}\right]$, then adj A will be :

Answer

(A)
$A _{11}=2, A_{12}=-1, A_{21}=-1, A_{22}=0$$
\operatorname{adj} A=\left[\begin{array}{ll}
A_{11} & A_{12} \\
A_{21} & A_{22}
\end{array}\right]^{\prime}=\left[\begin{array}{cc}
2 & -1 \\
-1 & 0
\end{array}\right]^{\prime}=\left[\begin{array}{cc}
2 & -1 \\
-1 & 0
\end{array}\right]
$
Hence correct option is (A).

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $\text{f(x)}=\begin{cases}\frac{|\text{x}+2|}{\tan^{-1}(\text{x}+2)}, & \text{x}\neq-2\\2, & \text{x}=-2\end{cases},$ then f(x) is:
  1. Continuous at x = -2
  2. Not continuous at x = -2
  3. Diffrentiable at x = -2
  4. Continuous but nit derivable at x = -2
If A and B are symmetric matrices of the same order, then:
  1. AB is a symmetric matrix.
  2. A - Bis askew-symmetric matrix.
  3. AB + BA is a symmetric matrix.
  4. AB - BA is a symmetric matrix.
If $|\vec{a}|=10,|\vec{b}|=2$ and $\vec{a} \cdot \vec{b}=12$, then the value of $|\vec{a} \times \vec{b}|$ is
A random variable $X$ takes the values $0, 1, 2, 3$ and its mean is $1.3.$ If $P(X = 3) = 2P(X = 1)$ and $P(X = 2) = 0.3,$ then $P(X = 0)$ is$:$
If $f(x)=\left\{\begin{array}{l}\frac{k x}{|x|} \text {, if } x<0 \\ 3, \text { if } x \geq 0\end{array}\right.$ is continuous at $x=0$, then the value of $k$ is
Choose the correct answer from the given four options.
The identity element for the binary operation * defined on $\text{Q}\sim\{0\}$ as $\text{a}\ ^*\ \text{b}=\frac{\text{ab}}{2}\ \forall\ \text{a, b}\in\text{Q}\sim\{0\}$ is:
  1. 1
  2. 0
  3. 2
  4. none of these.
The area of the region bounded by the ellipse $\text{x}^\frac{2}{16}+\text{y}^\frac{2}{9}=1$ is:
  1. $12\pi$
  2. $3\pi$
  3. $24\pi$
  4. $\pi$
Choose the correct option from given four options:
$\int\limits^{\frac{\pi}{4}}_{\frac{-\pi}{4}}\frac{\text{dx}}{1+\cos2\text{x}}$ is equal to:
  1. 1
  2. 2
  3. 3
  4. 4
if x lies in the interval $[0, 1],$ then the least value of $x^2 + x + 1$ is :
The interval in which the function $y=x^3+5 x^2-1$ is decreasing, is