Question
If $A =\left[\begin{array}{ll}1 & 3 \\ 3 & 4\end{array}\right] B =\left[\begin{array}{ll}-2 & 1 \\ -3 & 2\end{array}\right]$ and $A^2-5 B^2=5 C$ Find the matrix $C$ where $C$ is a $2$ by $2$ matrix.

Answer

$A^2=A \times A=p\left[\begin{array}{ll}1 & 3 \\ 3 & 4\end{array}\right]\left[\begin{array}{ll}1 & 3 \\ 3 & 4\end{array}\right]$
$\left[\begin{array}{cc}1 \times 1+3 \times 3 & 1 \times 3+3 \times 4 \\ 3 \times 1+4 \times 3 & 3 \times 3+34 \times 40\end{array}\right]$
$=\left[\begin{array}{cc}10 & 15 \\ 15 & 25\end{array}\right]$
$\begin{array}{l}B^2=B \times B=\left[\begin{array}{ll}-2 & 1 \\ -3 & 2\end{array}\right]\left[\begin{array}{ll}-2 & 1 \\ -3 & 2\end{array}\right]\end{array}$
$=\left[\begin{array}{ll}-2 \times-2+1 \times-3 & -2 \times 1+1 \times 2 \\ -3 \times-2+2 \times-3 & -3 \times 1+2 \times 2\end{array}\right]$
$=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$
Given: $A^2-5 B^2=5 C$
$\begin{array}{l}\Rightarrow\left[\begin{array}{ll}10 & 15 \\ 15 & 25\end{array}\right]-5\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]=5 C\end{array} $
$\Rightarrow\left[\begin{array}{ll}10 & 15 \\ 15 & 25\end{array}\right]-\left[\begin{array}{ll}5 & 0 \\ 0 & 5\end{array}\right]=5 C$
$\Rightarrow\left[\begin{array}{cc}5 & 15 \\ 15 & 20\end{array}\right]=5 C $
$ \Rightarrow 5\left[\begin{array}{ll}1 & 3 \\ 3 & 4\end{array}\right]=5 C$
$\Rightarrow C=\left[\begin{array}{ll}1 & 3 \\ 3 & 4\end{array}\right]$

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