If A = | , * 20 c 1&1&1 &b&c a^3 & b^3 & c^3 , |,B = | , * 20 c 1… - Vidyadip

MCQ

If $A = \left| {\,\begin{array}{*{20}{c}}1&1&1\\a&b&c\\{{a^3}}&{{b^3}}&{{c^3}}\end{array}\,} \right|,B = \left| {\,\begin{array}{*{20}{c}}1&1&1\\{{a^2}}&{{b^2}}&{{c^2}}\\{{a^3}}&{{b^3}}&{{c^3}}\end{array}\,} \right|,C = \left| {\,\begin{array}{*{20}{c}}a&b&c\\{{a^2}}&{{b^2}}&{{c^2}}\\{{a^3}}&{{b^3}}&{{c^3}}\end{array}\,} \right|,$ then which relation is correct

A
$A = B$
B
$A = C$
C
$B = C$
✓
None of these

✓

Answer

Correct option: D.

None of these

d
(d) It is obvious.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The modulus and amplitude of $\frac{{1 + 2i}}{{1 - {{(1 - i)}^2}}}$ are

Suppose $X$ follows a binomial distribution with parameters $n$ and $p$, where $0 < p < 1.$ If $\frac{{P\,(X = r)}}{{P\,(X = n - r)}}$ is independent of $n$ and $r$, then

$\mathop {\lim }\limits_{x \to \pi /6} \left[ {\frac{{3\sin x - \sqrt 3 \cos x}}{{6x - \pi }}} \right] = $

$\int {\frac{{{{\sin }^3}2x}}{{{{\cos }^5}2x}}dx = } $

Let $\alpha$ be a non-zero real number. Suppose $f: \mathrm{R} \rightarrow$ $\mathrm{R}$ is a differentiable function such that $f(0)=2$ and $\lim _{\mathrm{x} \rightarrow-\infty} \mathrm{f}(\mathrm{x})=1$. If $f^{\prime}(\mathrm{x})=\alpha f(x)+3$, for all $\mathrm{x} \in \mathrm{R}$, then $f\left(-\log _e 2\right)$ is equal to . . . . . . . . .

The number of $6$ digit numbers that can be formed using the digits $0, 1, 2, 5, 7$ and $9$ which are divisible by $11$ and no digits is repeated, is

If the function $f(x)=x^3+e^{\frac{x}{2}}$ and $g(x)=f^{-1}(x)$, then the value of $g^{\prime}(1)$ is

If the sum of the series

$\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{2^2}-\frac{1}{2.3}+\frac{1}{3^2}\right)+$

$\left(\frac{1}{2^3}-\frac{1}{2^2 \cdot 3}+\frac{1}{2.3^2}-\frac{1}{3^3}\right)+$

$\left(\frac{1}{2^4}-\frac{1}{2^3 \cdot 3}+\frac{1}{2^2 \cdot 3^2}-\frac{1}{2 \cdot 3^3}+\frac{1}{3^4}\right)+\ldots$ is $\frac{\alpha}{\beta}$, where $\alpha$ and $\beta$ are co-prime, then $\alpha+3 \beta$ is equal to....

The value of $\mathop {\lim }\limits_{x \to 0} \,\left( {\frac{{\int_0^{{x^2}} {{{\sec }^2}\,t\,dt} }}{{x\,\sin x}}} \right)\,$ is

The value of $\int_0^{2\pi } {{{\cos }^{99}}x\,dx} $ is