Question
If a line makes the angle $\alpha,\beta,\gamma$ with three dimensional coordinate axes respectively, then $\cos2\alpha+\cos2\beta+\cos2\gamma$ is equal to:
  1. -2
  2. -1
  3. 1
  4. 2

Answer

  1. -1

Solution:

We need to find value of $\cos2\alpha+\cos2\beta+\cos2\gamma$

It is further equal to $\cos^2\alpha-1+\cos^2\beta-1+\cos^2\gamma-1$

$=2\big(\cos^2\alpha+\cos^2\beta+\cos^2\gamma\big)-3$

$= 2(1) - 3 = 2 = -1$

$\therefore(\text{l}^2 + \text{m}^2 + \text{n}^2 = 1)$

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