MCQ
If a matrix $A$ is such that $3{A^3} + 2{A^2} + 5A + I = 0,$ then its inverse is
- ✓$ - (3{A^2} + 2A + 5I)$
- B$3{A^2} + 2A + 5I$
- C$3{A^2} - 2A - 5I$
- DNone of these
$\Rightarrow I = - 3{A^3} - 2{A^2} - 5A$
$ \Rightarrow $$I{A^{ - 1}} = - 3{A^2} - 2A - 5I$
$ \Rightarrow $ ${A^{ - 1}} = - (3{A^2} + 2A + 5I)$
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Statement $-1 :$ The probability that the chosen numbers when arranged in some order will form an $A.P.$ is $\frac{1}{{85}}$ .
Statement $-2 :$ If the four chosen numbers form an $A.P.$, then the set of all possible values of common difference is $\left( { \pm 1, \pm 2, \pm 3, \pm 4, \pm 5} \right)$ છે.