Question
If $a \neq 0$ and $a-\frac{1}{a}=3; $ find $:a^2+\frac{1}{a^2}$

Answer

$a-\frac{1}{a}=3$
$\left(a-\frac{1}{a}\right)^2=9$
$a^2+\frac{1}{a^2}=9+2$
$=11$

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