Question
If a parallelopiped is formed by planes drawn through the points (5, 8, 10) and (3, 6, 8) parallel to the coordinate planes, then the length of diagonal of the parallelopiped is:
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$2\sqrt{3}$
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$3\sqrt{2}$
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$\sqrt{2}$
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$\sqrt{3}$
If a parallelopiped is formed by planes drawn through the points (5, 8, 10) and (3, 6, 8) parallel to the coordinate planes, then the length of diagonal of the parallelopiped is:
$2\sqrt{3}$
$3\sqrt{2}$
$\sqrt{2}$
$\sqrt{3}$
Solution:
Given parallelepiped passes through A(5, 8, 10) and B(3, 6, 8)
$\therefore$ Length of the diagonal,
$\text{AB}=\sqrt{(5-3)^2+(8-6)^2+(10-8)^2}$ $=\sqrt{4+4+4}=2\sqrt{3}$
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