Question

If a parallelopiped is formed by planes drawn through the points (5, 8, 10) and (3, 6, 8) parallel to the coordinate planes, then the length of diagonal of the parallelopiped is:

  1. $2\sqrt{3}$

  2. $3\sqrt{2}$

  3. $\sqrt{2}$

  4. $\sqrt{3}$

Answer

  1. $2\sqrt{3}$

Solution:

Given parallelepiped passes through A(5, 8, 10) and B(3, 6, 8)

$\therefore$ Length of the diagonal,

$\text{AB}=\sqrt{(5-3)^2+(8-6)^2+(10-8)^2}$ $=\sqrt{4+4+4}=2\sqrt{3}$

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