Question
If a point 'C' lies between two points A and B such that AC = BC, then prove that  AC = $\frac{1}{2}$AB. Explain by drawing the figure.

Answer



Given, AC = BC
AC + AC = BC + AC . . . . [AC are added to both the side]
2AC = AB . . . . [BC + AC coincides with AB]
$\therefore$ AC = $\frac{1}{2}$AB

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