If a Second's pendulum is moved to a planet where acceleration due to gravity is $4$ times, the length of the second's pendulum on the planet should be made .......... times
A$2$
B$4$
C$8$
D$15$
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B$4$
b (b)
Time period of a pendulum
$T=2 \pi \sqrt{\frac{l}{g}} \text { or } T_2 \sqrt{\frac{1}{g}}$
If $g$ becomes $4$ times. I must also be increased by $4$ times to keep $T$ constant.
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