MCQ
If a solid sphere of mass $5\,kg$ and a disc of mass $4\,kg$ have the same radius. Then the ratio of moment of inertia of the disc about a tangent in its plane to the moment of inertia of the sphere about its tangent will be $\frac{x}{7}$. The value of $x$ is $.........$
  • A
    $4$
  • $5$
  • C
    $3$
  • D
    $2$

Answer

Correct option: B.
$5$
b
$I _1=\frac{2}{5} m _1 R ^2+ m _1 R ^2$

$I _1= m _1 R ^2\left(\frac{7}{5}\right)$

$I _1=7 R ^2$

$I _2=\frac{ m _2 R ^2}{4}+ m _2 R ^2$

$I _2=\frac{5}{4} m _2 R ^2$

$I _2=5 R ^2$

$\frac{ I _2}{ I _1}=\frac{5}{7}$

$x =5$

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