MCQ
If a solid sphere surface area $48 cm^2$ is bisected into two hemisphere , then the total surface area of any one of the hemisphere is
- A$48 cm^2$
- B$60 cm^2$
- C$24 cm^2$
- ✓$36 cm^2$
✓
Answer
Correct option: D.
$36 cm^2$
(d)
Letr be the radius of solid sphere. It is given that its total surface area is $48 cm^2$.
$4 \pi r^2=48 \Rightarrow \pi r^2=12 \Rightarrow 3 \pi r^2=36$
Hence, total surface area of one of the hemispheres is $36 cm^2$
Letr be the radius of solid sphere. It is given that its total surface area is $48 cm^2$.
$4 \pi r^2=48 \Rightarrow \pi r^2=12 \Rightarrow 3 \pi r^2=36$
Hence, total surface area of one of the hemispheres is $36 cm^2$
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