Let the perimeter of circle and square is $1$Then perimeter of circle $={2}\pi\text{r}$
$= 1$ (wherer is redius of circle) $\Rightarrow\text{r}=\frac{1}{2\pi}$
Then area of circle $ = \pi\text{r}^{2} = \pi(\frac{1}{2\pi})^{2} = \frac{1}{4\pi} = 0.0789$
perimeter of square $= 4l = 1$ then l $= \frac{1}{4}$ (where l id the side of square)
Then area of square $=\frac{1}{4}\times\frac{1}{4} = \frac{1}{16} = 0.0625$
Then area of circle is greater then that of squre
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