Question
If a vector$​​\vec{\text{a}}$ is perpendicular to two non-collinear vectors $\vec{\text{b}}$ and $\vec{\text{c}},$ then show that $​​\vec{\text{a}}$ is perpendicular to every vector in the plane of $\vec{\text{b}}$ and $\vec{\text{c}}.$

Answer

Given that $\vec{\text{a}}$ is perpendicular to $\vec{\text{b}}$ and $\vec{\text{c}}.$
$\Rightarrow\vec{\text{a}}.\vec{\text{b}}=0$ and $\vec{\text{a}}.\vec{\text{c}}=0\dots(1)$
Now, let $\vec{\text{r}}$ be any vector in the plane of $\vec{\text{b}}$ and $\vec{\text{c}}.$
Then, $\vec{\text{r}}$ is the linear combination of $\vec{\text{b}}$ and $\vec{\text{c}}.$
$\vec{\text{r}}=\text{x}\vec{\text{b}}+\text{y}\vec{\text{c}}, $ for some x and y.
Now,
$​​\vec{\text{a}}.​​\vec{\text{r}}$
$=​​\vec{\text{a}}.\big(\text{x}\vec{\text{b}}+\text{y}\vec{\text{c}}\big)$
$=\text{x}\big(\vec{\text{a}}.\vec{\text{b}}\big)+\text{y}\big(\vec{\text{a}}.\vec{\text{c}}\big)$
$=\text{x}(0)+\text{y}(0)$ [From(1)]
$=0$
Thus, $\vec{\text{a}}$ is perpendicular to $\vec{\text{r}}.$
That is, $\vec{\text{a}}$ is perpendicular to every vector in the plane of $\vec{\text{b}}$ and $\vec{\text{c}}.$

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