MCQ
If $A = [x:f(x) = 0]$ and $B = [x:g(x) = 0]$, then $A \cap B$ will be
  • ${[f(x)]^2} + {[g(x)]^2} = 0$
  • B
    $\frac{{f(x)}}{{g(x)}}$
  • C
    $\frac{{g(x)}}{{f(x)}}$
  • D
    None of these

Answer

Correct option: A.
${[f(x)]^2} + {[g(x)]^2} = 0$
a
(a) $A \cap B = \{ x:x \in A$ and $x \in B\} $

$ = [x:f(x) = 0$ and $g(x) = 0]$ $ = {[f(x)]^2} + {[g(x)]^2} = 0$.

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