MCQ
If $A^2=-\frac{1}{2}\left[\begin{array}{cc}1 & -4 \\ -1 & 2\end{array}\right]$ then $A=$
  • A
    $\left[\begin{array}{rr}2 & 4 \\ -1 & 1\end{array}\right]$
  • B
    $\left[\begin{array}{rr}2 & 4 \\ 1 & -1\end{array}\right]$
  • C
    $\left[\begin{array}{rr}2 & -4 \\ 1 & 1\end{array}\right]$
  • $\left[\begin{array}{rr}2 & 4 \\ 1 & 1\end{array}\right]$

Answer

Correct option: D.
$\left[\begin{array}{rr}2 & 4 \\ 1 & 1\end{array}\right]$
$-\frac{1}{2}\left[\begin{array}{ll}2 & 4 \\ 1 & 1\end{array}\right]$

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