MCQ
If a=3 and r=2 then find the sum up 5th term.
- A95
- B82
- C93
- D97
Solution:
We know, $\text{s}_\text{n}=a\frac{\text({r^\text{n}-1)}}{\text({r}-1)}$
Here a = 3, r = 2 and n = 5
$\text{s}_5=3\frac{(2^5-1)}{(2-1)}$
$=3(32-1)=3\times31=93.$
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Let S = set of points inside the square, T = the set of points inside the triangle and C = the set of points inside the circle. If the triangle and circle intersect each other and are contained in a square. Then
$\text{S}\cap\text{T}\cap\text{C}=\phi$
$\text{S}\cup\text{T}\cup\text{C}=\text{C}$
$\text{S}\cup\text{T}\cup\text{C}=\text{S}$
$\text{S}\cup\text{T} = \text{S}\cap\text{C}$