MCQ
If $a^3-(b-a)^3-b^3=k(a-b)$, then $k=$
  • A
    ab
  • B
    3 ab
  • C
    $-3 a b$
  • D
    3

Answer

B. 3 ab
We observe that $a+(b-a)+(-b)=0$.\[\begin{array}{ll}\therefore & a^3+(b-a)^3+(-b)^3=3 a(b-a)(-b) \\\Rightarrow & a^3-(b-a)^3-b^3=3 a b(a-b) \Rightarrow k(a-b)=3 a b(a-b) \Rightarrow k=3 a b\end{array}\]

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