Question
If $AB = 7.5\ cm$ and $CD = 2.5\ cm,$ construct a segment whose length is equal to:
$2AB + 3CD$
$2AB + 3CD$
✓
Answer
Given: $AB= 7.5cm$ and $CD = 2.5cm$ Draw $AB$ and $CD$
Draw a line/ and take point Eon it. Now, take a divider and open it such that the ends of both its arms are at $A$ and $B.$ Then, we lift the divider and place its one end at $E$ and other end (say $F$) on the line $1,$ as shown in the figure. Again, lift the divider and place its one end at $F$ and another end ($G$) on the line $1$, opposite to $E$. Now, reset the divider in such a way that the ends of its one hand are at $C$ and the end of other hand is at $D.$ Then, we lift the divider and place its one end at $G$ and another end (say $H$) on the line $1,$ opposite to $E$ as shown in the figure. Again, lift the divider and place its one end at $H$ and other end (say $I$) on the line $1,$ opposite to $E$ as shown in the figure. Again, lift the divider and place its one end at $I$ and another end (say $J$) on the line $1,$ opposite to $E$ as shown in the figure. $EG$ is required line segment, whose length is equal to $(2AB + 3CD).$
Draw a line/ and take point Eon it. Now, take a divider and open it such that the ends of both its arms are at $A$ and $B.$ Then, we lift the divider and place its one end at $E$ and other end (say $F$) on the line $1,$ as shown in the figure. Again, lift the divider and place its one end at $F$ and another end ($G$) on the line $1$, opposite to $E$. Now, reset the divider in such a way that the ends of its one hand are at $C$ and the end of other hand is at $D.$ Then, we lift the divider and place its one end at $G$ and another end (say $H$) on the line $1,$ opposite to $E$ as shown in the figure. Again, lift the divider and place its one end at $H$ and other end (say $I$) on the line $1,$ opposite to $E$ as shown in the figure. Again, lift the divider and place its one end at $I$ and another end (say $J$) on the line $1,$ opposite to $E$ as shown in the figure. $EG$ is required line segment, whose length is equal to $(2AB + 3CD).$
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