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Playing with Numbers — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSPlaying with Numbers1 Mark
Question
If $AB + 7C = 102, $ where $B ≠ 0, C ≠ 0,$ then $A + B + C = 14.$
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Answer

 Here, $B + C$ is either $2$ or a two- digit number whose one’s digit is $2.$ If $B = C = 1$, lf $8 = 5, C = 7, A = 2$ and $A + B + C = 2 + 5 + 7 = 14$

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