MCQ
If $a,\;b,\;c$ are in $A.P.$ and $a,\;b,\;d$ in $G.P.$, then $a,\;a - b,\;d - c$ will be in
- A$A.P.$
- ✓$G.P.$
- C$H.P.$
- DNone of these
$ \Rightarrow b = \frac{{a + c}}{2}$…..$(i)$
and ${b^2} = ad$….. $(ii)$
Hence $a,\;a - b,\;d - c$ are in $G.P. $ because
${(a - b)^2} = {a^2} - 2ab + {b^2} = a(a - 2b) + ad$
$ = a(a - a - c) + ad = ad - ac$.
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