MCQ
If $a+b+c=0$, then $\frac{a^2}{b c}+\frac{b^2}{c a}+\frac{c^2}{a b}=$
- A1
- B0
- C-1
- D3
✓
Answer
D. 3
We have, $a+b-c=0$
$\Rightarrow$ $a^3+b^3-c^2$ = 3 abc $\Rightarrow$ $\frac{a^3+b^3+c^3}{a b c}$ = 3 $\Rightarrow$ $\frac{a^2}{b c}+\frac{b^2}{c a}+\frac{c^2}{a b}$ =3
We have, $a+b-c=0$
$\Rightarrow$ $a^3+b^3-c^2$ = 3 abc $\Rightarrow$ $\frac{a^3+b^3+c^3}{a b c}$ = 3 $\Rightarrow$ $\frac{a^2}{b c}+\frac{b^2}{c a}+\frac{c^2}{a b}$ =3
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