MCQ
If AD, BE and CF are $\triangle\text{ABC},$ then $\vec{\text{AD}}+\vec{\text{BE}}+\vec{\text{CF}}$
- ✓$\vec{0}$
- B1
- C0
- D2
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$\left[\begin{array}{cc}
2 a+b & a-2 b \\
5 c-d & 4 c+3 d
\end{array}\right]=\left[\begin{array}{cc}
4 & -3 \\
11 & 24
\end{array}\right]$
$x+y+z=2$
$2 x+4 y-z=6$
$3 x+2 y+\lambda z=\mu$ has infinitely many solutions, then