MCQ
If $a\,.\,i = 4,$ then $(a \times j)\,.\,(2j - 3k) = $
- A$12$
- B$2$
- C$0$
- ✓$-12$
$ = a\,.\,\{ - 3(j \times k)\} = - 3(a\,.\,i) = - 12.$
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