Question
If $A=\left[\begin{array}{c}-1 \\ 2 \\ 3\end{array}\right], B=\left[\begin{array}{lll}3 & 1 & -2\end{array}\right]$, find $B^{\prime} A^{\prime}$

Answer

$\begin{array}{l} B ^{\prime} A ^{\prime}=\left[\begin{array}{lll}3 & 1 & -2\end{array}\right]^{\prime}\left[\begin{array}{c}-1 \\ 2 \\ 3\end{array}\right]^{\prime} \end{array}$
$ =\left[\begin{array}{c}3 \\ 1 \\ -2\end{array}\right]\left[\begin{array}{lll}-1 & 2 & 3\end{array}\right] $
$ =\left[\begin{array}{ccc}-3 & 6 & 9 \\ -1 & 2 & 3 \\ 2 & -4 & -6\end{array}\right]$

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